If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2+x-250=0
a = 5; b = 1; c = -250;
Δ = b2-4ac
Δ = 12-4·5·(-250)
Δ = 5001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{5001}}{2*5}=\frac{-1-\sqrt{5001}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{5001}}{2*5}=\frac{-1+\sqrt{5001}}{10} $
| y-35y=90 | | -12=-x+4x | | (1)/(2)x+4=(2)/(3)x | | 1+2m-7=-12 | | 9x^2+3x-7x-21=-9x^2-4x-21 | | 12y-11=9+12y | | 2*0+0y=10 | | 6m-5=-5-4m-m | | 1/4x=1/3x+3 | | 5y-2=33+5y | | 9x2+3x-7x-21=-9x2-4x-21=0 | | 1/3*x+x-90=0 | | 3/12x=-4/12x+3 | | -9x2-4x-21=0 | | 3/12x=-4/12+3 | | 3/4b-6=-4(1/4b-2) | | 8,523=8,000+x+20+3 | | 5a+3C=96 | | y/5+9=-12 | | -3x+5(3x-6)=-10-8x | | x^2+40x-2400=0 | | x/3-x+8=0 | | 5/3x-6=8+5/12x | | x^2-110x+2925=0 | | -5=x=-2 | | (5−x)1/2−2x=0(5−x)1/2−2x=0. | | 9x-81+4=9x+7 | | -14x^2+1680x-49,000=0 | | 9x^2+3x-7x-21=0 | | 3=-7b+6b | | 3/(y-4)= | | 0.2(x-4)=2 |